A flower bed is in the shape of a traingle with one side twice the length?

of the shortest side, and the third side is 18 feet more than the length of the shortest side. Find the dimensions if the perimeter is 178 feet?


A= ? feet(shortest side)


B= ? feet(second side)


C= ? feet(third side)
A flower bed is in the shape of a traingle with one side twice the length?
B=2A, C=A+18, A+B+C = 178.





Substitute 2A for B, and A+18 for C gives:





A + 2A + A+18 = 178,





or 4A+18 = 178, 4A=160, or A=40.





A=40


B=2A=80,


C=A+18=58
Reply:It%26#039;s easy.





Take 178 and subtract 18 = 160





Take the 180 and divide by 4 = 40





40 is the shortest side





40x2 = 80 is the longest side





40+18 = 58 is the last side





40+80+58 = 178





A=40


B=58


C=80
Reply:side 1, 2, 3= a,b,c (note, not the same as A,B,C)





one side twice the length of shortest: b = 2a


third side c , 18 ft more than shortest: c =a+ 18





perimeter a + b+ c = 178


a + (2a) + (a+18)= 178


4a +18 = 178


4a = 160


a = 40





with a -40, b = 80 , c = 58


so, shortest, a, is A = 40, B = 58, C = 80
Reply:?make up